Question

LAST QUESTION!! PLZ HELP!!

Answer 1

@jim_thompson5910 think u can help with this last question of mine?

Answer 2

remember wolfram?

Answer 3

yah i tried that but i couldn't figure out how to use it. & mathway wasn't letting me do it.

Answer 4

ok the basic format again is

normalcdf(a,b,mu,sigma)

Answer 5

where [a,b] is your interval

mu = mean
sigma = standard deviation

Answer 6

ok i get what mu & sigma mean but my problem was i was i couldn't figure out how to get the standard deviation cause idk what n is.

Answer 7

well in this case, the standard deviation is sigma

you don't use the formula sigma/sqrt(n)

Answer 8

because you're not looking at the xbar distribution

Answer 9

but a & b are 54 & 69, & the mean is 50?

Answer 10

yep

a = 54
b = 69
mu = 50
sigma = 7

Answer 11

normalcdf(a,b,mu,sigma)

becomes

normalcdf(54,69,50,7)

Answer 12

type that in and look at the last row in the "probabilities" section

Answer 13

so the answer would be 0.2805?

Answer 14

correct

Answer 15

THANK U! u really are my life saver! lol

Answer 16

lol glad to be of help