Question

simplify and reduce to lowest terms 1/x+4

Answer 1

\[\frac{ 1 }{ x}+4\]

Answer 2

can you explain me how to get that?

Answer 3

thats the actuall problem that needs to be simplified and reduced

Answer 4

I don't know how \[\frac{1}{x+4}=\frac{1}{x}+ 4\]

Answer 5

i thought it would be \[\frac{ 5 }{ x+4 }\]

Answer 6

@sndrod09 do you know how to get an LCD?

Answer 7

i thinkso

Answer 8

ok, so bearing in mind that \(\large 4=\frac{4}{1}\) then
$$
\cfrac{1}{x}+\cfrac{4}{1} = \cfrac{}{\boxed{LCD?}}
$$

Answer 9

mulitplyby 1?

Answer 10

lCD =1

Answer 11

orisit x

Answer 12

I guess I meant the LCM :S

Answer 13

1x would be LCMright ?

Answer 14

maybe not, it'd be the LCD, anyhow, lemme get the definition correct ehhehe

Answer 15

an yhow, it's lcd, or lowest ... well, a number/term, you DIVIDE by ALL denominators

Answer 16

so, say for the denominators, 3 and 6, a common will be "6", because, 6/3 = 2, and 6/6 =1, now, 5, won't work to produce an integer in this case, so that won't work, 13 is not divisible by 3 or 6, so that won't work either

Answer 17

right so am i just making up a number for x?

Answer 18

x can be any real number right ?

Answer 19

well, in this case, yes

Answer 20

http://www.math.com/school/subject1/images/SIU3L3GL.gif

they call it the LCM there, but is the same thing, the lcd :|

Answer 21

withthat being the case the answer shouldbe 5/x

Answer 22

hmm, do you know how to add fractions?

Answer 23

or\[\frac{ 4x+1 }{ x }\]

Answer 24

DUETOME MULTIPLYING 4(x)/1(x)

Answer 25

ding :D
$$
\cfrac{1}{x}+\cfrac{4}{1} = \cfrac{1+4x}{x} \implies \cfrac{4x+1}{x}
$$

Answer 26

sweetthanks