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OpenStudy (anonymous):
\[5^{3x}=0.04\]
sam (.sam.):
Have you learnt natural logarithm before?
OpenStudy (anonymous):
not to good at it
sam (.sam.):
If you ln both sides,
\[\ln(5^{2x})=\ln(0.04)\]
------------------------
Using rule
\[\ln(a^b)=b \ln(a)\]
------------------------
\[2x \ln(5)=\ln(0.04)\]
Divide both sides by 2ln(5) and you're done
OpenStudy (anonymous):
maan that is confusing
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OpenStudy (anonymous):
what doi do with the 2x?
sam (.sam.):
The last part?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
i reallydon t' understand In either. IS there a formula i should know
sam (.sam.):
You want to get x alone, so
\[\color{red}{2}x \color{red}{\ln(5)}=\ln(0.04)\]
\[x=\frac{\ln(0.04)}{2\ln(5)}\]
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sam (.sam.):
The formula we used here is just \(\ln(a^b)=b \ln(a)\), you need to practice more of them
OpenStudy (anonymous):
x=-4?
sam (.sam.):
Nope
sam (.sam.):
For \(x=\frac{\ln(0.04)}{2\ln(5)}\) you can just use a calculator for that
OpenStudy (anonymous):
do i multiply 2 by ln(5)?
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