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Mathematics 17 Online
OpenStudy (anonymous):

solve

OpenStudy (anonymous):

\[5^{3x}=0.04\]

sam (.sam.):

Have you learnt natural logarithm before?

OpenStudy (anonymous):

not to good at it

sam (.sam.):

If you ln both sides, \[\ln(5^{2x})=\ln(0.04)\] ------------------------ Using rule \[\ln(a^b)=b \ln(a)\] ------------------------ \[2x \ln(5)=\ln(0.04)\] Divide both sides by 2ln(5) and you're done

OpenStudy (anonymous):

maan that is confusing

OpenStudy (anonymous):

what doi do with the 2x?

sam (.sam.):

The last part?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

i reallydon t' understand In either. IS there a formula i should know

sam (.sam.):

You want to get x alone, so \[\color{red}{2}x \color{red}{\ln(5)}=\ln(0.04)\] \[x=\frac{\ln(0.04)}{2\ln(5)}\]

sam (.sam.):

The formula we used here is just \(\ln(a^b)=b \ln(a)\), you need to practice more of them

OpenStudy (anonymous):

x=-4?

sam (.sam.):

Nope

sam (.sam.):

For \(x=\frac{\ln(0.04)}{2\ln(5)}\) you can just use a calculator for that

OpenStudy (anonymous):

do i multiply 2 by ln(5)?

OpenStudy (anonymous):

i got -4still

OpenStudy (anonymous):

how about x=-2/3

OpenStudy (anonymous):

the answer is not a fraction

OpenStudy (anonymous):

\[x=\frac{ \ln 0.04 }{ \ln 25}=-1\] \[5^{5\times(-1)}=0.04\]

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