An arch of a bridge is built in the shape of a half an ellipse. it has a span of 100ft. The height of the arch is 30ft from the center is 16ft. Find the height at the center.
Let's find a formula for the ellipse: \[(x-50)^2+ay^2=2500\]seems to work. Find a by plugging x=30 or x=-30 in for x, 16 for y, and solving for a.
Then, use that formula with x=50 and solve for y.
so the height then would be 17.5ft?
Sorry, you should have plugged in 20 or 80, I miswrote.
20 or 80 for which variable?
For x in the initial process to find a. I said 30 or -30 when that's for the entire term.
how'd you get that? the 20 or 80, where'd it come from?
Those are what you need to be 30 feet from the center.
so I enter either 20 or 80 initially as x then. how do I know what to put in as x the second time as I find the height, y
|dw:1368323781573:dw|
That will have a simpler formula: \[x^2+ay^2=2500\] Just insert 30 or -30 for x the first time and find a using 16 for y, then insert x=0 and solve for y.
you mean insert 20 or 80 in for x right?
Not that formula, I simplified the situation by placing the origin in the middle of the river.
Ah, alright
so then it's 20 ft tall in the center
Yup!
Awesome thanks so much!
Join our real-time social learning platform and learn together with your friends!