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Mathematics 18 Online
OpenStudy (anonymous):

An arch of a bridge is built in the shape of a half an ellipse. it has a span of 100ft. The height of the arch is 30ft from the center is 16ft. Find the height at the center.

OpenStudy (anonymous):

Let's find a formula for the ellipse: \[(x-50)^2+ay^2=2500\]seems to work. Find a by plugging x=30 or x=-30 in for x, 16 for y, and solving for a.

OpenStudy (anonymous):

Then, use that formula with x=50 and solve for y.

OpenStudy (anonymous):

so the height then would be 17.5ft?

OpenStudy (anonymous):

Sorry, you should have plugged in 20 or 80, I miswrote.

OpenStudy (anonymous):

20 or 80 for which variable?

OpenStudy (anonymous):

For x in the initial process to find a. I said 30 or -30 when that's for the entire term.

OpenStudy (anonymous):

how'd you get that? the 20 or 80, where'd it come from?

OpenStudy (anonymous):

Those are what you need to be 30 feet from the center.

OpenStudy (anonymous):

so I enter either 20 or 80 initially as x then. how do I know what to put in as x the second time as I find the height, y

OpenStudy (anonymous):

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OpenStudy (anonymous):

That will have a simpler formula: \[x^2+ay^2=2500\] Just insert 30 or -30 for x the first time and find a using 16 for y, then insert x=0 and solve for y.

OpenStudy (anonymous):

you mean insert 20 or 80 in for x right?

OpenStudy (anonymous):

Not that formula, I simplified the situation by placing the origin in the middle of the river.

OpenStudy (anonymous):

Ah, alright

OpenStudy (anonymous):

so then it's 20 ft tall in the center

OpenStudy (anonymous):

Yup!

OpenStudy (anonymous):

Awesome thanks so much!

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