Question

y = -cot(x + pie/6) - 3

graphing a trig function please help me!!!!!

Answer 1

http://www.wolframalpha.com/input/?i=y+%3D+-cot%28x+%2B+pi%2F6%29+-+3+

Answer 2

thx its just a little confusing on there

Answer 3

take the graph of \(y=\cot(x)\)

shift it to the left \(\frac{\pi}{6}\) units
that gives \(y=\cot(x+\frac{\pi}{6})\)

then turn it upside down to get \(y=-\cot(x+\frac{\pi}{6})\)

then translate it down 3 units to get
\[y=-\cot(x+\frac{\pi}{6})-3\]

Answer 4

one question tho

Answer 5

like if im starting at pie/4 interval how can i get to pie/6 ?

Answer 6

you can't

Answer 7

so than like how do i lable the graph its so confusing

Answer 8

there is no \(\frac{\pi}{4}\) in the problem

Answer 9

the interval

Answer 10

here is a picture of \(y=\cot(x)\)
you see it has a vertical asymptote at \(0\) and at \(\pi\) and also that it is zero at \(\frac{\pi}{2}\)

Answer 11

http://www.wolframalpha.com/input/?i=cot%28x%29

Answer 12

you want to shift it to the left \(\frac{\pi}{6}\) units, so instead of the vertical asymptote at \(0\) and \(\pi\) they will be at \(-\frac{\pi}{6}\) and \(\frac{5\pi}{6}\)

Answer 13

-cot and cot are the same thing?

Answer 14

no

Answer 15

i was just trying to get the graph of \(y=\cot(x+\frac{\pi}{6})\) first , then we can turn it upside down

Answer 16

i.e. see that you are going to shift it to the left \(\frac{\pi}{6}\) units
here it is
http://www.wolframalpha.com/input/?i=cot%28x%2Bpi%2F6%29

Answer 17

you can compare the graphs and see that the second one is identical to the first, only shifted left \(\frac{\pi}{6}\) now we can flip it

Answer 18

last, question how would u label it
and thanks a lot

Answer 19

http://www.wolframalpha.com/input/?i=-cot%28x%2Bpi%2F6%29
asymptotes are the same, now it is upside down

Answer 20

and finally we can drop it by 3 units to finish the question, and get this graph
http://www.wolframalpha.com/input/?i=-cot%28x%2Bpi%2F6%29-3

Answer 21

thanks

Answer 22

if you want to label the \(x\) axis, you probably best label the zero and the asymptotes

Answer 23

yea im just confused, if it starts at -pi/6 do i label it by going up pi/6?

Answer 24

instead of it being at \(0\) and \(\pi\) as i said before, label the asymptotes at \(-\frac{\pi}{6}\) and \(\frac{5\pi}{6}\)

Answer 25

ok yea

Answer 26

and 11pi/6

Answer 27

right, the next one would be \(\frac{11\pi}{6}\)