x=8sqrtx
\[x=8\sqrt{x}\]
I know what the answer is just by looking at it, I just forgot how to actually get the answers
what the question?
that is it x=8sqrtx
if you mean the directions it just says solve
square from both sides, that's the 1st step
ok did that
and get x^2 and 8x
now, u have x^2 = 64x or x^2 - 64x = 0
oh you would distribute that?
factor out! x(x-64)=0 solve for x
ok but the answers are 0 and 64
that method gives you 0, 8 and -8
x(x-64)=0 the zeroes satisfies when each factor be zero x = 0 or x-64=0 ----> x=64
ahhh okay
so you don't totally factor it out?
you just like half retriceit?
they are cant be 8 and -8
1) Observe the trivial solution x = 0 2) Observe Domain Restrictions in the ORIGINAL expression. \(x \ge 0\) 3) NOW square both sides.
ok do I put that in parenthesis
oh I see, I didn't know that when you square a side with a radical you have to do it to the term in front of the radical and the radical itself right?
yes, (sqrt(x))^2 = x
Why would "both sides" mean "only part of one side"? The WHOLE thing!
yea I got that TK I know this im talking about the one term with the number in front of the radical like this |dw:1368338979058:dw|
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