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Mathematics 16 Online
OpenStudy (anonymous):

x=8sqrtx

OpenStudy (anonymous):

\[x=8\sqrt{x}\]

OpenStudy (anonymous):

I know what the answer is just by looking at it, I just forgot how to actually get the answers

OpenStudy (anonymous):

what the question?

OpenStudy (anonymous):

that is it x=8sqrtx

OpenStudy (anonymous):

if you mean the directions it just says solve

OpenStudy (raden):

square from both sides, that's the 1st step

OpenStudy (anonymous):

ok did that

OpenStudy (anonymous):

and get x^2 and 8x

OpenStudy (raden):

now, u have x^2 = 64x or x^2 - 64x = 0

OpenStudy (anonymous):

oh you would distribute that?

OpenStudy (raden):

factor out! x(x-64)=0 solve for x

OpenStudy (anonymous):

ok but the answers are 0 and 64

OpenStudy (anonymous):

that method gives you 0, 8 and -8

OpenStudy (raden):

x(x-64)=0 the zeroes satisfies when each factor be zero x = 0 or x-64=0 ----> x=64

OpenStudy (anonymous):

ahhh okay

OpenStudy (anonymous):

so you don't totally factor it out?

OpenStudy (anonymous):

you just like half retriceit?

OpenStudy (raden):

they are cant be 8 and -8

OpenStudy (tkhunny):

1) Observe the trivial solution x = 0 2) Observe Domain Restrictions in the ORIGINAL expression. \(x \ge 0\) 3) NOW square both sides.

OpenStudy (anonymous):

ok do I put that in parenthesis

OpenStudy (anonymous):

oh I see, I didn't know that when you square a side with a radical you have to do it to the term in front of the radical and the radical itself right?

OpenStudy (raden):

yes, (sqrt(x))^2 = x

OpenStudy (tkhunny):

Why would "both sides" mean "only part of one side"? The WHOLE thing!

OpenStudy (anonymous):

yea I got that TK I know this im talking about the one term with the number in front of the radical like this |dw:1368338979058:dw|

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