Solve the following quadratic equation by completing the square: x2 + 5x - 3 = 0

A. (-5+√37)/2, (-5 -√37)/2
B. (5+√37)/2, (5 -√37)/2
C. (-5+√13)/2, (-5 -√13)/2
D. No real solution

Question

Solve the following quadratic equation by completing the square: x2 + 5x - 3 = 0 



 A. (-5+√37)/2, (-5 -√37)/2 
 B. (5+√37)/2, (5 -√37)/2 
 C. (-5+√13)/2, (-5 -√13)/2 
 D. No real solution

anonymous · Answer

another  i need help is Solve for x by completing the square: 4x2 + 6x - 6 = 0 



 A. (-3+√33)/4, (-3-√33)/4 
 B. (3+√33)/4, (3-√33)/4 
 C. 3, -2 
 D. 1, 6

anonymous · Answer

completing: $$x^{2} + bx = (x + (b/2))^{2} - (b/2)^{2}$$

anonymous · Answer

gotta go sorry lol

anonymous · Answer

its okay thanks :D

primeralph · Answer

first off, divide all by a = 4

anonymous · Answer

$$x^2+  5x-  3 =0  \\ x^2+   5x=  3  \  x^2+   5x +(\frac{ 5 }{2})^2 = 3 +(\frac{5   }{2})^2\\ x^2+   5x  +  (\frac{ 25 }{4})= 3 + (\frac{ 25 }{4})\\ (  x    +  \frac{ 5 }{2}  )^2  =  \frac{37 }{4}  \\ x  =  - \frac{ 5 }{2}  \pm   \frac{ \sqrt{ 37 }}{  2}   \\x  =  - \frac{ 5   -  \sqrt{ 37 }}{2} ,   - \frac{ 5    +  \sqrt{ 37 }}{2}    $$