Question

find the derivative

Answer 1

\[\frac{ d }{ dx }\int\limits_{0}^{x ^{3}}\sin t dt\]

Answer 2

\[=\frac{d}{dx} [-\cos(x^{3})-(-\cos(0))]\]
\[= \frac{d}{dx} 1-\cos(x^{3})\]
\[= 3x^{2} \sin(x^{3})\]

Answer 3

seems right to me. are you sure?

Answer 4

yes
http://www.wolframalpha.com/input/?i=differentiate+integral+sin%28t%29+dt+from+0+to+x%5E3

Answer 5

i could not figure out how to type those limits in wolfram

Answer 6

so i had to ask it here

Answer 7

thanks

Answer 8

ahh ok ....yw