Question

Help me with part b.

Answer 1

tree diag?

Answer 2

Maybe you can't have 1 black and 1 red too?!

Answer 3

yes @Callisto

Answer 4

Hmm You are going to pick two balls only..

Answer 5

Yes

Answer 6

P(X+Y<2) = P(1 black 1 green) + P(1 black 1 red) + P(2 green)
I guess :|

Answer 7

There can't be 1 black and 1 red as 1+1=2

It would be P(1 black 1 green)+P(1red 1 green)+P(all green)

Answer 8

I just need a confirmation that it would be like this :/

Answer 9

Ok..

Answer 10

so am i right?

Answer 11

I guess yes..
*PS: I'm terrible in probability!

Answer 12

okay what would be the probability like.
I mean

is P(bg)=(3/8)*(3/8)

Answer 13

No?!

Answer 14

then?

Answer 15

P(1 Black 1 green) = P(black then green) + P(green then black)
P (black then green) = 3/8 * 3/7

Answer 16

how do you know its with or without replacement?

Answer 17

I supposed it is without replacement.

Answer 18

okay thanks.

Answer 19

@Callisto What about part (e)?

Answer 20

@ash2326