can you find the derivative of y = ln|1 + x| ? Is there a caught when we have somehing like |....| ?
\[\Large\frac{d }{dx} \ln f(x)=\frac{ f'(x) }{ f(x) }\]
there |...| is unneccessary since the defination of ln functi0on desires it to be positive
(lnabs(1+x))=(ln(x+1) )'=1/(x+1)
What is the anti-derivative of 1/x?
lnabsx
exactly
Then if I differentiate that, I get back to 1/x. Similarly, what would be the antiderivative of 1/x+1? What would be the derivative of this antiderivative that you just got?
@Christos
y = |1+x| y = sqrt((1+x)^2) squares to both sides : y^2 = (1+x)^2 now, take the derivative by using implicit, 2y dy = 2(1+x)(1)dx dy/dx = 2(1+x)/2y dy/dx = (1+x)/y subtitute back, that y = |1+x| so, dy/dx = (1+x)/|1+x|
does that make sense ?
thank you
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