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does fibonacci converge ?
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Nope. Do you recall the following:\[\bf \lim_{n \rightarrow \infty}\frac{ f _{n+1} }{ f _{n} }=\phi \approx 1.618...\] The ratio of the next and previous terms of the sequence is always greater than 1, but for a series to converge, the terms of the sequence must approach 0, but here that doesn't happen. Each term is larger than the one before and;\[\bf \lim_{n \rightarrow \infty} f_{n} \ne 0\]
@Jonask
yes the golden ratio so it diverges since by ratio test this will mean \[\huge \frac{ a_{n+1} }{ a_n } \ge 1\]
mhm
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