At what temperature would 0.600 mole of a gas at 700. torr have a volume of 22.6 L?

Question

anonymous · Answer

ok..i will work on it. thank you

anonymous · Answer

i convert mol to l?

frostbite · Answer

@chmvijay using Charles law suggest you should use two volumes not one, think it would be more appropriate to assume the gas is a perfect gas and use the perfect gas equation, don't you?

chmvijay · Answer

yaaaa sorry use Pv=nRT
i just got confused :)

frostbite · Answer

I would rather say you should try:
$$pV=nRT \rightarrow T=\frac{ pV }{ nR }$$
T: temperature
p : pressure
V : volume
n : amount of substance
R : gas constant (R=kNa)

anonymous · Answer

i got 40.19 K

anonymous · Answer

but i need C...what's the formula for converting from K to c?

frostbite · Answer

40,19 K? try recalculate that.

anonymous · Answer

i'll tell you waht i did..converted torr to atm= 700torr(1atm/760torr)=.921atm

anonymous · Answer

.921x22.6L/ (0.600x0.08210)=

chmvijay · Answer

K=°C +273

anonymous · Answer

ok..yea..i did it again..i got the right answer..i don't know where i typed wrong numbers into the computer....sorrry, i have a headache, am tired and am over this class :-P

frostbite · Answer

sorry meant K^-1

frostbite · Answer

But you got the same answer now?

anonymous · Answer

yes i did..thank you very much

frostbite · Answer

$$T=\frac{ 700 torr*22.6 L }{ 62.364 \frac{ Torr*L }{ K*mol }*0.6 mol }=422.789 K$$

frostbite · Answer

Perfect just, edited the equation as I wrote wrong :)

chmvijay · Answer

LOL