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OpenStudy (ksaimouli):

what is total KE of two pucks before collision

OpenStudy (ksaimouli):

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OpenStudy (ksaimouli):

@Vincent-Lyon.Fr

OpenStudy (vincent-lyon.fr):

Just add up the two KE of the pucks.

OpenStudy (ksaimouli):

ok but when should i consider the x and y direction

OpenStudy (vincent-lyon.fr):

KE is a scalar quantity, depending on speed, not on velocity. So no need here to bother with x's and y's.

OpenStudy (ksaimouli):

okay so if i want to find the momentum then it is

OpenStudy (chmvijay):

1/2 mv^2

OpenStudy (chmvijay):

MV is momentum

OpenStudy (vincent-lyon.fr):

Momentum is a vector quantity depending on velocity. So x's and y's have to be considered properly.

OpenStudy (ksaimouli):

okay but if they ask te magnitude of total momentum of the 2 pucks system after collision

OpenStudy (ksaimouli):

the answer is 5J i did not get

OpenStudy (ksaimouli):

the KE is 5J because it is scalar but why the total momentum 5J

OpenStudy (vincent-lyon.fr):

Start again with KE and forget momentum right now. 5J is the right answer.

OpenStudy (ksaimouli):

yes

OpenStudy (ksaimouli):

now they are asking total momentum of the pucks

OpenStudy (ksaimouli):

after collision

OpenStudy (chmvijay):

what will be the kinetic energy after collision ??

OpenStudy (vincent-lyon.fr):

Value of total momentum is 5 kg.m/s, it is not 5 J. (different units)

OpenStudy (vincent-lyon.fr):

Total momentum before collision = total momentum after collision (always true)

OpenStudy (ksaimouli):

ya i know that but we dont know whether it is elastic or inelastic

OpenStudy (ksaimouli):

for KE to be conserved

OpenStudy (vincent-lyon.fr):

Hold on! Can you ask/answer questions one at a time? It's totally confusing.

OpenStudy (chmvijay):

LOL:)

OpenStudy (ksaimouli):

alright consider the same diagram (2) what is teh total momentum of two puck system after collision

OpenStudy (vincent-lyon.fr):

Well, it's the same as BEFORE the collision, so what you have to do is work out total momentum before collision.

OpenStudy (ksaimouli):

got you thx for replying

OpenStudy (chmvijay):

Since the two momentum vectors are at right angles, their sum can be found using the Pythagorean theorem; the direction can be found using SOH CAH TOA (specifically, the tangent function)

OpenStudy (chmvijay):

http://www.physicsclassroom.com/mmedia/momentum/2di.cfm this may help you LOL

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