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Mathematics 15 Online
OpenStudy (anonymous):

evaluate the integral by using multiple substitutions

OpenStudy (anonymous):

\[∫\frac{ \sin \sqrt{t} }{ \sqrt{tcos ^{3}\sqrt{t}} }dt\]

OpenStudy (anonymous):

this is equal to: \[=\int\limits_{}^{}\frac{ \sin(\sqrt{t}) }{ \sqrt{t}\cos^{3/2}(\sqrt{t}) }\] let u = cos(sqrt(t)) du = \[\frac{ - \sin{\sqrt{t}} dt }{ 2 \sqrt{t} }\]

OpenStudy (anonymous):

what is the next step?

OpenStudy (anonymous):

\[= -(1/2) \int\limits_{}^{} \frac{ du }{ u^{3/2} }\]

OpenStudy (anonymous):

\[-\frac{ 2 }{ t \frac{ 3 }{ 2 } }+c\]

OpenStudy (anonymous):

none of the answers seem to be the one you gave. except this one looks kinda close

OpenStudy (anonymous):

integral of that is u^(-1/2) = \[\frac{ 1 }{ \sqrt{\cos{\sqrt{t}}} }\]

OpenStudy (anonymous):

multiplied by 4

OpenStudy (anonymous):

\[\frac{ 4 }{ \sqrt{\cos \sqrt{t}} }+c\]

OpenStudy (anonymous):

divided by 2 twice when i should have multiplied. sorry. not using paper >.<

OpenStudy (anonymous):

is another possible answer but im notsure

OpenStudy (anonymous):

you got it

OpenStudy (anonymous):

its the answer i have

OpenStudy (anonymous):

100% sure

OpenStudy (anonymous):

the last one i just gave?

OpenStudy (anonymous):

\[-\frac{ 4 }{ \sqrt{\cos \sqrt{t}} }+c\]

OpenStudy (anonymous):

positive 4

OpenStudy (anonymous):

ok so this without the negative?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

are you sure?

OpenStudy (anonymous):

100%

OpenStudy (anonymous):

did it on paper

OpenStudy (anonymous):

ok thanks

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