can someone help me find the derivative of this
f(x)=x^2-4x/\[\sqrt{x}\]
\[\frac{x^2-4x}{\sqrt{x}}\]?
yes
probably easiest to divide first and write in exponential notation
\[x^{\frac{3}{2}}-4x^{\frac{1}{2}}\]
then you can use the power rule for both terms
that help?
how did you get that
i divided each term by \(\sqrt{x}\) using exponential notation that is not the answer, that is just a step along the way
how come you wouldnt bring up the x?
\[\frac{x^2}{x^{\frac{1}{2}}}=x^{\frac{3}{2}}\] for the first ter,m
in simple english, i subtracted \(\frac{1}{2}\) from each exponent in the numerator
\[\frac{x^2-4x}{\sqrt{x}}=\frac{x^2-4x}{x^{\frac{1}{2}}}\]\[=x^{2-\frac{1}{2}}-4x^{1-\frac{1}{2}}=x^{\frac{3}{2}}-4x^{\frac{1}{2}}\]
just using exponential notation, so now you can use the power rule to get the derivative
okay i get it thanks!
yw btw a lot of calc problems are much easier when you have everything written in exponential notation the power rule makes otherwise hard calculators very easy
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