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OpenStudy (anonymous):
can someone help me find the derivative of this
13 years ago
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OpenStudy (anonymous):
f(x)=x^2-4x/\[\sqrt{x}\]
13 years ago
OpenStudy (anonymous):
\[\frac{x^2-4x}{\sqrt{x}}\]?
13 years ago
OpenStudy (anonymous):
yes
13 years ago
OpenStudy (anonymous):
probably easiest to divide first and write in exponential notation
13 years ago
OpenStudy (anonymous):
\[x^{\frac{3}{2}}-4x^{\frac{1}{2}}\]
13 years ago
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OpenStudy (anonymous):
then you can use the power rule for both terms
13 years ago
OpenStudy (anonymous):
that help?
13 years ago
OpenStudy (anonymous):
how did you get that
13 years ago
OpenStudy (anonymous):
i divided each term by \(\sqrt{x}\) using exponential notation
that is not the answer, that is just a step along the way
13 years ago
OpenStudy (anonymous):
how come you wouldnt bring up the x?
13 years ago
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OpenStudy (anonymous):
\[\frac{x^2}{x^{\frac{1}{2}}}=x^{\frac{3}{2}}\] for the first ter,m
13 years ago
OpenStudy (anonymous):
in simple english, i subtracted \(\frac{1}{2}\) from each exponent in the numerator
13 years ago
OpenStudy (anonymous):
\[\frac{x^2-4x}{\sqrt{x}}=\frac{x^2-4x}{x^{\frac{1}{2}}}\]\[=x^{2-\frac{1}{2}}-4x^{1-\frac{1}{2}}=x^{\frac{3}{2}}-4x^{\frac{1}{2}}\]
13 years ago
OpenStudy (anonymous):
just using exponential notation, so now you can use the power rule to get the derivative
13 years ago
OpenStudy (anonymous):
okay i get it thanks!
13 years ago
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OpenStudy (anonymous):
yw
btw a lot of calc problems are much easier when you have everything written in exponential notation
the power rule makes otherwise hard calculators very easy
13 years ago
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