Question

what is the derivative of cosh(1/(x+e^x))?

Answer 1

not to bad but kind of ugly chain rule for this one

Answer 2

what is the derivative of \(\cosh(x)\) ?

Answer 3

-sin h (x)

Answer 4

no i don't think so

Answer 5

this is what i got... -sinh(1/(x+e^x) (1x+e^x)^-2 + (1+e^x)

Answer 6

you are getting that confused with the derivative of sine being minus cosine

Answer 7

i thought the derivative of sin is just cos

Answer 8

the derivative of \(\cosh(x)\) is \(\sinh(x)\)

Answer 9

and the derivative of cos is negative sin

Answer 10

really?

Answer 11

yeah i wrote that backwards
what i meant is you are getting it confused with the derivative of cosine being minus sine

Answer 12

woahhh i didn't know that

Answer 13

so is it just what i wrote negated.

Answer 14

sinh(1/(x+e^x))(x+e^x)^-2+1+e^x?

Answer 15

then you need the chain rule

Answer 16

you get
\[\sinh(\frac{1}{x+e^x})\times \frac{d}{dx}[\frac{1}{x+e^x}]\]