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Mathematics 10 Online
OpenStudy (anonymous):

Find x int and y int of the function: 2x^3-13x^2+22x-8

OpenStudy (anonymous):

I know I can find them just by graphing,, but I need to know how to do it algebraically

OpenStudy (e.mccormick):

\(2x^3-13x^2+22x-8 \) I am going to assume that is =0?

OpenStudy (e.mccormick):

Or =y...

OpenStudy (e.mccormick):

Factor it, set it to 0, solve each factor. Those are the x intercepts.

OpenStudy (e.mccormick):

The y intercept is easy. It is a gimmie. Set x to 0. Poof. All x terms are gone. What is left is the y intercept.

OpenStudy (anonymous):

i think he knows this. he wants to know how to factor a third-order polynomial.

OpenStudy (anonymous):

exactly

OpenStudy (anonymous):

I know what the answers are I don't know how to factor a third degree polynomial

OpenStudy (e.mccormick):

Ah, that is a little longer topic than I can take on when going to bed... hmmmm... Heard of the rational roots theorem? http://www.purplemath.com/modules/rtnlroot.htm They may have covered that one recently in your class, or may be about to.

OpenStudy (anonymous):

we already did im just reviewing for finals lol, but thanks!

OpenStudy (e.mccormick):

Ah, kk. Well, that is the sort of method they normally go for. A lot of times I just try a couple logical guesses based on the terms because most things that are meant to be factored usually have one easy one. Once that is divided out, I can solve the rest a number of ways. I have seen a nice method for quadratics recently, but not for 3rd order plus.

OpenStudy (campbell_st):

if you use the rational root theorem then the factors of 8 over the factor of 2 will give a rational root... so use the remainder theorem for f(2) just as a guess.... if it equals zero then you have a root... then a little division and factoring will give the other roots or intercepts. just a thought

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