The force acting between two charged particles A and B is 5.2 x 10^-5 newtons. Charges A and B are 2.4 x 10^-2 meters apart. If the charge on particle A is 7.2 x 10^-8 coulombs, what is the charge of particle B? (k = 9.0 * 10^9 newton·meters^2/coulomb^2

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anonymous · Answer

can yahll please help me

hyper · Answer

This question would fit in the physics section however as its already here, I'll try to answer it. To answer this question, Coulombs law is required which is F = kq1q2/r^2
Therefore, rearranging for q2 , 
q2 = Fr^2/kq1 = (5.2 x 10^-5) x (2.4 x 10^-2)^2/(9.0 * 10^9) x (7.2 x 10^-8) 
which equals q2 = 4.62 x 10^-11 Coulombs