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Chemistry 20 Online
OpenStudy (anonymous):

Help please somebody check my answers! & explain if they are wrong why?

OpenStudy (anonymous):

OpenStudy (anonymous):

@thomaster check my answers please?

OpenStudy (chmvijay):

e and g are wrong

OpenStudy (chmvijay):

Al is oxidised and H2O is reduced

OpenStudy (chmvijay):

can you do the e and g once again :)

OpenStudy (anonymous):

so is e = -1? @chmvijay

OpenStudy (chmvijay):

NOOO [Al(OH)4 ]- now can you

OpenStudy (anonymous):

and hydrogen is 1?

OpenStudy (anonymous):

im confused so is it 0 for e?

OpenStudy (chmvijay):

you consider Whole OH has -1 charge then there are 4 OH gives how many charges

OpenStudy (anonymous):

-3

OpenStudy (anonymous):

so g = -1?

OpenStudy (chmvijay):

if charge on one OH is -1 then what is total charge on 4 OH - i am asking

OpenStudy (anonymous):

-1 + 4?

OpenStudy (anonymous):

=3?

OpenStudy (chmvijay):

yaaa Al is +3 i thought u got it

OpenStudy (anonymous):

yes so.. for g is -1 right?

OpenStudy (chmvijay):

NOOO OH whole charge is -1 mean bcoz O is -2 and H is +1

OpenStudy (anonymous):

wait i knew that. sorry . SO h = 1.

OpenStudy (anonymous):

and wasn't Aluminum reduced and Hyrdogen was oxidized?

OpenStudy (chmvijay):

yaa and in 3 rd question you got confused i think you wrote opposite i think you will rectify it can you ??

OpenStudy (chmvijay):

did Al has lost its electron in reaction or gained the electrons can you tell me Al -----> Al+3 in the reaction right

OpenStudy (anonymous):

Al has gained?

OpenStudy (anonymous):

@chmvijay

OpenStudy (anonymous):

oxidized means looses and reduction means to gain right?

OpenStudy (chmvijay):

right LOL how +3 charge mean what it has gained

OpenStudy (chmvijay):

do you know why its +3 charge on Al

OpenStudy (anonymous):

because it was oxidized?

OpenStudy (chmvijay):

when it is oxidsed what happens

OpenStudy (anonymous):

the Oxygen and hyrdogen looses electrons.

OpenStudy (anonymous):

so its the other way around. Al was oxidized and hydrogen was reduced? :O

OpenStudy (anonymous):

alright thank you! @chmvijay

OpenStudy (chmvijay):

ur welcome :)

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