Question

The equation... :)

Answer 1

what do u think @terenzreignz ? :)

Answer 2

Wrong. This time, I'm sure...
\[\Large \tan(\alpha + \beta) = \frac{\tan(\alpha) + \tan(\beta)}{1-\tan(\alpha)\tan(\beta)}\]

Answer 3

hhaa okay :P darn :(

Answer 4

okay, so i'm looking for something that follows that format right?

Answer 5

incidentally, you'd do well to recall that
\[\Large \tan \ \frac \pi 6 = \frac1{\sqrt3}\]

Answer 6

haha yeah :P

Answer 7

So following that rule, we have
\[\large \tan \left(x + \frac \pi 6\right)= \frac{\tan(x) +\tan \frac \pi 6}{1-\tan(x)\tan\left(\frac \pi 6\right)}\]

Answer 8

okay, so that simplifies to tan(x)+1/sq.rt. 3 / 1-tan(x)(1/sq.rt. 3 ??

Answer 9

That's right... so multiply it by \(\Large \frac{\sqrt 3}{\sqrt 3}\)

Answer 10

oh wait sorry haha so it's between B and D then? :/

Answer 11

Which one? You can't have both...

Answer 12

i think it's D... is that right? :)

Answer 13

Yeah.

Answer 14

awesome! haha thanks a bunch!! :D