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y'=t-1+y^2 . . . How to solve? Cannot be linear first order ODE due to the y^2, can it?
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t=-y^2+y+1
Another way of writing it is -t-y^2+y+1 = 0
Try letting:\[y(t) = t \eta(t) \implies \dot y = \eta(t) + t \dot{\eta}(t) \implies \eta(t)+t \dot \eta (t) = t - 1 + t^2 \eta^2(t)\] From here you could try laplace transforms and get something then convert back?
I can assume that this is a parabola
blast234, what are you talking about?
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I think I did it wrong I did not watch out for the ' in the Y
My bad XD
In general there is no way to solve non-linear ODEs every time, I just threw out a technique I've seen used.
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