Question

The sum of the lengths of the diagonals of a rhombus is 20, AE is x + 4, BE is 2x - 3. What is the length of BD? please help!

Answer 1

\[BD = 2\times BE\]
so

\[BD = 2 (2x -3)\]

just distribute for the answer

Answer 2

is it 24x?

Answer 3

nvm..... -__- is it 6?

Answer 4

and you also know that

\[AC = 2 \times AE\]

or

\[AC = 2(x + 4)\]

so distribute to find AC

next you know

BD + AC = 20

so substitute your information, collect like terms

then solve the equation for x.

hope this helps.

Answer 5

so when you distribute what did you get for

BD ?

Answer 6

uhm i believe its 6

Answer 7

not quite

BD = 4x - 6

now what about AC?

Answer 8

its 4?

Answer 9

nope... try

AC = 2x + 8

so the diagonals add to a length of 20

so

BD + AC = 20

or

4x - 6 + 2x + 8 = 20

can you collect like terms...?

Answer 10

oh its either 3 or 8 than

Answer 11

what is..?BD

Answer 12

3

Answer 13

nope

the sum of the diagonals is

6x + 2 = 20

so the value of x = 3

now earlier I said

BD = 4x - 6

substitute x = 3 into the equation to find BD

Answer 14

than its 8 cause thats the only option i have left.

Answer 15

wait.....it would be 6

Answer 16

nope so

\[BD = 4\times 3 - 6\]

BD = ?


rather than randomly guess... this question required to to use some algebra basics to come up with an answer...

when you post

3

8

6

include some information so that the person helping knows what you are describing.