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For a solution with a hydrogen ion concentration of 3.48x10^-8 M determine pH - pOH - (OH-)
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pH = -log[H] same with pOH.
Given [H+] = 3.48x10^-8 M Take the negative log of the concentration to get pH: -log(3.48x10^-8) = 7.46 pH pOH is just 14 - pH: 14 - 7.46 = 6.54 pOH Use 10^(-pOH) to find concentration of pOH: 10^(-6.54) = 2.87x10^-7 M = [OH-]
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