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subtract: (3/x-3) - (5/x-2)
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you need a common denominator of (x -3)(x - 2) so you have \[\frac{3(x -2)}{(x -3)(x-2)} - \frac{5(x -3)}{(x -3)(x-2)}\] just distribute the numerators and collect like terms... then you'll have an answer
thnks so much
so it can be written as \[\frac{3(x -2) - 5(x -3)}{(x -3)(x-2)}\]
so.. 2x+9/(x-3)(X-2)
when you distribute the 3 and the -5 the top becomes 3x -6 -5x +15 how do you get +2x ? Isn't it -2x +9
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i didnt put a +2
what is this? so.. 2x+9/(x-3)(X-2)
ya thts a plus 9
nevermind
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