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Mathematics 8 Online
OpenStudy (anonymous):

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OpenStudy (espex):

This is the type of question that you will need to get your hands dirty and solve.

OpenStudy (espex):

So how far have you made it?

OpenStudy (anonymous):

dont even understand what they want me to do with it

OpenStudy (espex):

To start with, they are asking you to solve the two equations, you can factor them and solve for your x's or you can use the quadratic equation and solve for your roots.

OpenStudy (anonymous):

well this whole chapters about quadratic equations ... so im guessing this thats what we would use to solve for the roots

OpenStudy (anonymous):

@eSpeX

OpenStudy (espex):

Technically speaking, if a polynomial has a variable raised to a power then it is a quadratic equation. Both of your equations here are quadratic: \[0 = x^2 + 5x + 6 \]\[ 0 = x^2 + 4x + 4\] Most of these can be solved by factoring, breaking the equation into parts and solving each piece: \[x^{2}+10x+16 \rightarrow (x+2)(x+8)=0\]\[x+2=0\rightarrow x=-2\]\[x+8=0\rightarrow x=-8\] The above procedure is what you need to use to solve your equations. When solving for roots I mistyped "equation" when I intended to say "formula". You use the quadratic formula to solve for roots \[\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\]

OpenStudy (anonymous):

oh alright i get it , can u help me with part 2 ?

OpenStudy (anonymous):

i suck with equations -.- Part 2: Using complete sentences, answer the following questions about the two quadratic equations above. Do the two quadratic equations have anything in common? If so, what? What makes y = x2 + 4x + 4 different from y = x2 + 5x + 6?

OpenStudy (precal):

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