Evaluate the integral x*e^(-2x) dx
I started out by using Integration by parts (IBP). I let u=e^(-2x) and dv= xdx. Therefore du= -2e^(-2x)dx and v= x^2/2. I multiplied U times V and then subtracted the integral of Vdu. I'm not sure where I'm going wrong.

Question

Evaluate the integral x*e^(-2x) dx 
I started out by using Integration by parts (IBP). I let u=e^(-2x) and dv= xdx. Therefore du= -2e^(-2x)dx and v= x^2/2. I multiplied U times V and then subtracted the integral of Vdu. I'm not sure where I'm going wrong.

primeralph · Answer

first off, you look pretty.
Okay, what you want to do is swap your u and dv. Let dv  = e^blah blah, and u = x, so that dx can reduce x to 1 (which is easier to solve)

tiffany_rhodes · Answer

okay, I'll try that then and thank you :)