What is the value of the x variable in the solution to the following system of equations? 2x + 3y = 4 x - 2y = -5 @eSpeX
@cshalvey @robtobey
You can use elimination to quickly solve for 'x', however using substitution will work as well.
How would I do the elimination way?
Elimination involved "eliminating" one of the variables, in this case, y. So you multiply each equation by a number that will allow you to get the 'y' values equal.
multiply the second by -2 and add both equations
What do you get if you multiply the two 'y' coefficients together?
6y, right?
Right, so what would you need to multiply into equation 1 to have 6y and in equation 2 to get -6y?
I have no clue, this is confusing.
In equation 1, you have 3y, so you need to multiply by 2 to get 6y. You must multiply the entire equation to keep from changing it, so (2)(2x+3y=4) => (2*2x)+(2*3y)=(2*4) to give you 4x+6y=8 You do the other one.
Do the same with multiplying by 2 ?
If 2 times the 'y' will give you a 6
Oh, ok. Maybe I should use 3 then.
Exactly, good job.
3x - 6y = -15
Excellent. Now you want to add these two equations together, so x+x, y+y, and total + total: 4x +6y = 8 3x -6y = -15 And your resulting equation will allow you to solve for 'x' and get the answer to this problem. :)
7x + 12y = -7 ?
@jim_thompson5910
6y + (-6y) is not 12y
Oh, I didn't notice it was -6y
Is the answer -1
x = -1, yep
use that to find y
All I needed was x.
But thanks.
oh true, but it doesn't hurt to find y (for practice)
True. I'll write it down and try it when I finish these next questions.
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