Question

Given: DE is a midsegment of
Prove: triangle ABC similar to DBE
Can somebody please help me work this problem out, I don't just want the answer it'd be much appreciated!

Answer 1

Hint: You have to show that

BA/BD = BC/BE

Answer 2

So first I would have to start with the equation? It says that this is a 30-60-90 degree triangle so I would have to use the 5 sqrt 3 to start it right?

Answer 3

no you would lead up to that equation

Answer 4

and i don't see anywhere it says that it's a 30-60-90 triangle

Answer 5

or wait sorry I wrote the wrong one lol

Answer 6

Sorry about that I was writing on the second question on my oral component. So that's all I would have to do for the answer of this question?

Answer 7

no there's a bit more, but that's basically one of the pieces you need

Answer 8

After that's set up what would be the next step to finding the solution Jim?

Answer 9

no you have to lead up to it, it's not the first thing you set up

Answer 10

Hmm... Im sorry Jim im just a tad bit confused on this question on how to get the solution and the steps so I have to lead up to that part of the question?

Answer 11

probably best to draw it out first

Answer 12

we know ED is a midsegment, so we know that

AD = BD
BE = EC

Answer 13

Oh okay so would I state a theorem to prove that these are similar?

Answer 14

yes, but that comes later

Answer 15

ok what would come next?

Answer 16

With the theorem being stated would that be the solution?

Answer 17

If AD = DB, then what is AB

Answer 18

AB = BC ?
or

Answer 19

what is AB equal to in terms of DB

Answer 20

I thought it would be BC but would it be equal to the midsegment?

Answer 21

how many times can you fit DB into AB

Answer 22

twice?

Answer 23

so AB = 2*DB, see how this works out?

Answer 24

A litle bit Im trying to understand a little better... still a little bit un-easy about it so it comes out to AB=2(DB) After this comes together whats next?

Answer 25

what does BC equal in terms of BE

Answer 26

BA?

Answer 27

fill in the blank

BC = ___*BE

Answer 28

BC=BA(BE)?

Answer 29

how many BE lengths can you fit in BC

Answer 30

Oh okay BC=2(BE)

Answer 31

good, you're getting the hang of it

Answer 32

notice how

BA/BD = 2*BD/BD = 2

and how

BC/BE = 2*BE/BE = 2

-------------------

this proves that

BA/BD = BC/BE

is true

Answer 33

Oh Okay so to prove it fully you have to compare kind of the two triangles in a equation to show that they are similar? Thanks Jim I really appreciate it :)

Answer 34

well you would use the fact that BA/BD = BC/BE is true

and the fact that angle B = angle B (reflexive property)

that builds up to the use of the SAS similarity property to show that the two triangles are similar

Answer 35

Thanks Jim, I have one more question if you don't mind if your not busy I could use some help figuring out? Then ill get out of your hair I don't want to be a burdon lol

Answer 36

Given the special right triangle, please find the short leg and the hypotenuse if the long leg is 5 sqrt 3 .

Answer 37

use this template