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OpenStudy (anonymous):

-x^2-2x+24=0

OpenStudy (anonymous):

-x^2-2x+24=0

OpenStudy (anonymous):

someone please help me

OpenStudy (anonymous):

U can think that a=-1, b=-2, c=24 ok

OpenStudy (anonymous):

Now, we star u solve the problem

OpenStudy (anonymous):

With that problem we will have x always gives 2 answers

OpenStudy (anonymous):

i dont know how to work it out, i miss class for a week so i dont have any notes

OpenStudy (anonymous):

1) X=( -b + square delta T) /2a, 2) x= -b - square delta T ) / 2 a , so u will get can answer. U find delta T by the way b ^2-4ac

OpenStudy (anonymous):

U do understand ?

OpenStudy (anonymous):

use quadratic equation. do you know how to use it?

OpenStudy (anonymous):

no im highly confused, could u just break it down for me

geerky42 (geerky42):

Can you factor it?

OpenStudy (anonymous):

you could and leave the negative sign on the outside

OpenStudy (anonymous):

nooo i dont think you can.....

OpenStudy (anonymous):

no i have to solve it

geerky42 (geerky42):

You could do this thing: -x² - 2x + 24 = 0 -(x² + 2x - 24) = 0 x² + 2x - 24 = 0 Now you can factor it easily. Is this clear? Factoring it is faster way to solve. Faster than using quadratic equation.

geerky42 (geerky42):

You know how to factor? No?

OpenStudy (anonymous):

Ok let me right it down for u to easy understand

OpenStudy (anonymous):

Ok let galacticwaves xx did it

OpenStudy (anonymous):

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a}\] and you know that \[ax^2+bx+c=0\] from the 2nd equation you can tell by looking at your problem what a, b, and c is

OpenStudy (anonymous):

Exactly what I said, good jobs men

OpenStudy (anonymous):

i still need help

OpenStudy (anonymous):

now what you have to do is plug in a, b and c into the 1st equation i put up above haha thank you as long as we speak the same language we succeed

OpenStudy (anonymous):

@jkjk1 now can you do that and let me see what you get for x

OpenStudy (anonymous):

i cant i really need help

OpenStudy (anonymous):

hmmm ok i will first tell you that a=-1 b=-2 and c=24 you can see how i go this from the 2nd equation i posted up, correct?

OpenStudy (anonymous):

could u give me the answer, i have to go to class at 6:30

OpenStudy (anonymous):

???

OpenStudy (anonymous):

then from plug in the values of a, b, and c onto the quadratic equation which is the 1st equation i posted up \[x=\frac{ -(-2) \pm \sqrt{(-2)^2-4(-1)(24)} }{ 2(-1) }=\frac{ 2 \pm \sqrt{4+96} }{ -2 }=\frac{ 2 \pm \sqrt{100} }{ -2 }\]

OpenStudy (anonymous):

and you get x=-6 and x=4

geerky42 (geerky42):

You would be grateful if you know how to factor; in this way you don't have to do all these work lol...

OpenStudy (anonymous):

He can u factor geeky, can u tell ur way?

OpenStudy (anonymous):

let me see how you can factor this out because i don't think it is possibl

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