Series solution of a second order differential equation with non-constant coefficients: I can find the solution to an equation of the form (d^2y/dx^2) + y = 0 but what if the zero was replaced with another value, say x^2? Would it be brought over to make the equation equal to zero or would it be dealt with during the recurrence relation?
What are you trying to solve exactly?
I've come across several examples where the question asks: Determine a series solution for the following differential equation about x=x(subscript zero). One example is (d^2y/dx^2) + y = 0. I have no problem obtaining a solution for said examples. I'm curious as to how the process changes when the given equation does not equal zero but something else, say x squared.
I believe when you solve for the recurrence the sums will pick out one value (namely n = 2 in a sum of x^n).
I was thinking of doing that. Is that all that needs to be done? So what if the question was: Determine a series solution for the following differential equation about x=x0: \[(x^2-1)*(d^2y/dx^2) -8x(dy/dx) + 20y = 6x^2\]
I get \[y=a0(1+10x^2+5x^4) + a1(x+2x^3+x^5/5) - x^4/2\]Is that a valid answer?
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