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OpenStudy (anonymous):
\[\sum_{n-1}^{10?}6(2)^{n}\]
OpenStudy (primeralph):
is that n =1 or n-1?
OpenStudy (anonymous):
Pretty sure it's 1...
OpenStudy (anonymous):
n=1
OpenStudy (primeralph):
@Dido525 just trying to clean things up ya know?
@onelove94 just do it term by term
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OpenStudy (anonymous):
it is n-1
OpenStudy (primeralph):
okay............
OpenStudy (anonymous):
Well then...
OpenStudy (anonymous):
yeah...that's why I am confused
OpenStudy (primeralph):
got like a screenshot or sth?
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OpenStudy (anonymous):
I know the answer is 12, 276...I am suppose to be correcting this problem and explaining why it is that answer but I just don't understand it....all the problems in my book are n=a number, not n- ... I don't know, maybe it was a typo
OpenStudy (primeralph):
yeah, so try using n=1 and let us hear what you get.
OpenStudy (anonymous):
I got 30,780
OpenStudy (primeralph):
no, I got the answer at the back.....not what you got.....
OpenStudy (anonymous):
what? sorry...
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OpenStudy (primeralph):
how did you do the sigma?
OpenStudy (anonymous):
I have no clue....I looked in my book and tried my hardest to piece it all together :/
OpenStudy (primeralph):
okay, a sigma works this way: simply plug in the first n =1, then n=2 and add each evaluation until the top n= 10.