How do you find the sum of this geometric series:
\[\sum_{n-1}^{10?}6(2)^{n}\]
is that n =1 or n-1?
Pretty sure it's 1...
n=1
@Dido525 just trying to clean things up ya know? @onelove94 just do it term by term
it is n-1
okay............
Well then...
yeah...that's why I am confused
got like a screenshot or sth?
I know the answer is 12, 276...I am suppose to be correcting this problem and explaining why it is that answer but I just don't understand it....all the problems in my book are n=a number, not n- ... I don't know, maybe it was a typo
yeah, so try using n=1 and let us hear what you get.
I got 30,780
no, I got the answer at the back.....not what you got.....
what? sorry...
how did you do the sigma?
I have no clue....I looked in my book and tried my hardest to piece it all together :/
okay, a sigma works this way: simply plug in the first n =1, then n=2 and add each evaluation until the top n= 10.
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