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Mathematics 8 Online
OpenStudy (anonymous):

How do you find the sum of this geometric series:

OpenStudy (anonymous):

\[\sum_{n-1}^{10?}6(2)^{n}\]

OpenStudy (primeralph):

is that n =1 or n-1?

OpenStudy (anonymous):

Pretty sure it's 1...

OpenStudy (anonymous):

n=1

OpenStudy (primeralph):

@Dido525 just trying to clean things up ya know? @onelove94 just do it term by term

OpenStudy (anonymous):

it is n-1

OpenStudy (primeralph):

okay............

OpenStudy (anonymous):

Well then...

OpenStudy (anonymous):

yeah...that's why I am confused

OpenStudy (primeralph):

got like a screenshot or sth?

OpenStudy (anonymous):

I know the answer is 12, 276...I am suppose to be correcting this problem and explaining why it is that answer but I just don't understand it....all the problems in my book are n=a number, not n- ... I don't know, maybe it was a typo

OpenStudy (primeralph):

yeah, so try using n=1 and let us hear what you get.

OpenStudy (anonymous):

I got 30,780

OpenStudy (primeralph):

no, I got the answer at the back.....not what you got.....

OpenStudy (anonymous):

what? sorry...

OpenStudy (primeralph):

how did you do the sigma?

OpenStudy (anonymous):

I have no clue....I looked in my book and tried my hardest to piece it all together :/

OpenStudy (primeralph):

okay, a sigma works this way: simply plug in the first n =1, then n=2 and add each evaluation until the top n= 10.

OpenStudy (primeralph):

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