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Mathematics 19 Online
OpenStudy (anonymous):

Find the derivative of Sinx using definition of derivative

OpenStudy (primeralph):

that's a little long and you got to know some identities.

OpenStudy (anonymous):

=lim(h->0) (sin(x+h) - sinx)/h =lim(h->0) (2cos(x+h/2) *sin(h/2))/h =lim(h->0) (cos(x+h/2) *sin(h/2))/h/2 =lim(h->0)(cos(x+h/2) * lim(h/2->0) sin(h/2))/h/2 =lim(h->0)(cos(x+h/2)*1 [lim(h/2->0) sin(h/2))/h/2 =1 ] =cosx

OpenStudy (anonymous):

much appreciated thanks

OpenStudy (anonymous):

welcome

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