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Mathematics 20 Online
OpenStudy (anonymous):

inequality question?

OpenStudy (anonymous):

\[5- 4x \div 3x ^{2} - x - 4 < 4\]

OpenStudy (e.mccormick):

Going to depend on what is divided by what. Generally, inequalities are solved in the same basic way as equalities. Get x alone, there is the answer. The caveat is that inequalities have different rules for getting x alone. Multiplying or dividing by a negative flips the inequality.

OpenStudy (anonymous):

ughh, what ?

OpenStudy (anonymous):

@Luis_Rivera what? for question or @e.mccormick comment cause i didn't understand what he meant?

OpenStudy (anonymous):

and (5-4x)/(3x2-x-4)<4

OpenStudy (e.mccormick):

Well, that was my question part. \[\frac{5-4x}{3x^2-x-4}<4\]

OpenStudy (anonymous):

thats the question

OpenStudy (anonymous):

i am solving this for half an hour but no big success

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

i only reached till this point (21-12x2)/(3x2-x-4)<0

OpenStudy (anonymous):

@Luis_Rivera don't laugh man i have exam in 4 hours!!

OpenStudy (e.mccormick):

Did you ever try factoring the bottom?

OpenStudy (anonymous):

no

OpenStudy (e.mccormick):

Get to fully factored form, then make a truth table.

OpenStudy (anonymous):

@e.mccormick k factoring the bottom is done now we have 3 roots \[\pm \sqrt{7}\div2\]

OpenStudy (anonymous):

-1 and 4/3

OpenStudy (anonymous):

u mean the number line table

OpenStudy (e.mccormick):

OK, so those points would be false no matter what. They are DNEs.

OpenStudy (e.mccormick):

\[\frac{3(7-4x^2)}{(3x-4)(x+1)}\]

OpenStudy (e.mccormick):

Now, that top does factor as a difference of squares if you use \(\sqrt{7}\) as one of them.

OpenStudy (anonymous):

k solving this i got \[ x \in (-\infty,-\sqrt{7}\div2)\cup(-1,\sqrt{7}\div2)\cup(4\div3,infty)\]

OpenStudy (anonymous):

is this correct

OpenStudy (e.mccormick):

I have not worked the truth table. As long as your holes are avoided and it is always <0, it should be correct. Did you run up test points in those ranges?

OpenStudy (anonymous):

yes its satisfying the equation

OpenStudy (e.mccormick):

Good, good. yah, as long as your DNE spots are out of the answer space and the test points between all critical points are in, then you should be safe. I did a writeup on somethign similar for domains of roots.

OpenStudy (anonymous):

thanks

OpenStudy (e.mccormick):

np. The paper is a page and a half. It explains the concept for the truth table. The thing you had an issue with here was really just not doing the facotring. Once it is factored, then the concept of a truth table is easier to apply.

OpenStudy (anonymous):

ohh

OpenStudy (anonymous):

thanks @e.mccormick and buy guys

OpenStudy (e.mccormick):

Ah, I think Luis_Rivera was looking at mine with a "Huh" type reaction. Not yours. Or if yours, the same question I had, what is divided.

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