what is the acceleration of a ring rolling without slipping?
holy crap you actually have that as a question?? im so sorry. im sure if you google it, you will find something.
no..i tried..but it gave me the results of a cylinder and a sphere only.. if u can answer then please tell me the formula of it's acceleration and force of friction
It is zero, as for all rolling objects if you do not push them.
Well let a ring of radius "r" be rolling witout slipping with 'linear' acceleration "a" and angular acc. "Z"...then each and every point on the ring has a linear acceleration as "a"in the same direction.. now as the ring is rolling, a=r(cross)Z=rZ(angle b/w a and rZ is 90) now direction of "rZ"varies from point to point let there b any point P on the ring as shown, making an angle (90-p) with "a" or "p" with the horizontal...So the net accn at point P is given by the vectorial sum of "a" and "rZ" here it =[a^2+(rZ)^2+2a(rZ)cos(90-p)]^1/2 hopefully it is explained bt plz confirm if i am all correct.. |dw:1368516461376:dw|
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