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Physics 6 Online
OpenStudy (anonymous):

what is the acceleration of a ring rolling without slipping?

OpenStudy (anonymous):

holy crap you actually have that as a question?? im so sorry. im sure if you google it, you will find something.

OpenStudy (anonymous):

no..i tried..but it gave me the results of a cylinder and a sphere only.. if u can answer then please tell me the formula of it's acceleration and force of friction

OpenStudy (vincent-lyon.fr):

It is zero, as for all rolling objects if you do not push them.

OpenStudy (anonymous):

Well let a ring of radius "r" be rolling witout slipping with 'linear' acceleration "a" and angular acc. "Z"...then each and every point on the ring has a linear acceleration as "a"in the same direction.. now as the ring is rolling, a=r(cross)Z=rZ(angle b/w a and rZ is 90) now direction of "rZ"varies from point to point let there b any point P on the ring as shown, making an angle (90-p) with "a" or "p" with the horizontal...So the net accn at point P is given by the vectorial sum of "a" and "rZ" here it =[a^2+(rZ)^2+2a(rZ)cos(90-p)]^1/2 hopefully it is explained bt plz confirm if i am all correct.. |dw:1368516461376:dw|

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