Question

Which of the following is the vertex of the quadratic equation y = -4(x + 6)2 + 2?

Answer 1

Can't get much better than this :)
If your quadratic equation is of the form...
\[\LARGE y = a(x-\color{red}h)^2+\color{blue}k\]
Then your vertex is the point...
\[\LARGE (\color{red}h,\color{blue}k)\]

Answer 2

i still dont understand

Answer 3

In that form of the equation (which, understandably, is called the vertex form), we have...
\[\LARGE y = -4(x+6)^2+2\]

In this scenario, which numbers are our h and k?

Answer 4

\[\LARGE y = a(x-\color{red}h)^2+\color{blue}k\]

Answer 5

6=h 2=k

Answer 6

Not quite, but close... as you can see, in the standard form, h is positive if it is accompanied by a minus (-) sign... so if in your equation, 6 is accompanied by a plus (+) sign, then h must be equal to...?

Answer 7

positive 6

Answer 8

Nope. if h = +6, then our equation has the form...
\[\LARGE y = a(x-\color{red}h)^2+\color{blue}k\]
\[\LARGE y = a(x-\color{red}{(+6)})^2+\color{blue}2\]
\[\LARGE y = a(x-\color{red}6)^2+\color{blue}2\quad \ne\quad a(x+6)^2+2\]