Suppose the general term of a sequence is T(n)=n^(2)-10n+18.
(a) Which two terms of the sequence are equal to 2?
Ans: 2nd and 8th (GOT IT)
>>>>(b) Is 200 a term in the sequence?
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OpenStudy (anonymous):
@Peter14
OpenStudy (anonymous):
so you're looking for 200=n^2-10n+18
solve it like a quadratic equation
OpenStudy (anonymous):
n=19.38749457 OR -9.38749457
OpenStudy (anonymous):
for a sequence you can only use integral values of n
OpenStudy (anonymous):
so does the sequence have a term=200?
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OpenStudy (anonymous):
ummm... substitute n=19/20??
OpenStudy (anonymous):
what?
OpenStudy (anonymous):
errr....
OpenStudy (anonymous):
is it the factor=the term 200?
OpenStudy (anonymous):
when I learned about sequences the teacher said that you can only use integral values of n
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OpenStudy (anonymous):
i know
OpenStudy (anonymous):
since the two values that would make x^2-10x+18=200 are not integral, 200 is not a term in the sequence. does that make any sense?
OpenStudy (anonymous):
ah, so if n is integer, then 200 is the answer?
OpenStudy (anonymous):
if you can get 200 by putting an integer in for n, 200 would be a term in the sequence.
OpenStudy (anonymous):
oh, i understood now:) thanks
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