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Mathematics 14 Online
OpenStudy (anonymous):

Help with integral criterion

OpenStudy (anonymous):

You have to post the question

OpenStudy (anonymous):

I shall show that \[\sum_{n=2}^{∞}\frac{ \ln(n)^p }{ n }\] is convergent if p <-1 and divergent if p> -1. I have to use the integral criterion. So before I can use the integral criterion I have to show that the series is positive, continuous and decreasing. Can somebody please help me?

OpenStudy (anonymous):

Dang, I could never do that......

OpenStudy (amistre64):

show the derivative of (ln(x)^p)/x has is always negative for the decreasing part

OpenStudy (anonymous):

The derivative of (ln(x)^p)/x is \[\frac{ p*\ln(x)^p }{ x^2 }-\frac{ \ln(x)^p }{ x^2 }=\frac{ \ln(x)^p*(p-\ln(x) }{ x^2*\ln(x) }\] How can I show that? @amistre64

OpenStudy (anonymous):

|dw:1368537982834:dw| I guess u need to find that not derivative

OpenStudy (amistre64):

is that part of the integral criterion tho?

OpenStudy (amistre64):

and is that ln^p or ln(x^p)? \[\frac{ \ln(x)^p }{ x }\] \[\frac{ x\frac{x^{p-1}}{x^p}-ln(x)^p}{x^2}\] \[\frac{ xx^{-1}-ln(x)^p}{x^2}\] \[\frac{ -ln(x)^p}{x^2}\]

OpenStudy (anonymous):

|dw:1368538259656:dw|

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