Question

16x²-8x+1=0

Answer 1

This a graph question?

Answer 2

2) 2x²-7x+3=0
3)2x²-x-6=0
4)9x²-3x-2=0
5)y²-6y+2=0
6)4x²-20x+25=0
7)4x²-7x-15=0

Answer 3

no its not they are solving quadratic equations all of them

Answer 4

you can solve it by one of the ways used for quadratic equations, like you can try it by using quadratic formula [x=b \pm \sqrt{b ^{2}-4ac}\div2a\]

Answer 5

i dont know how thats the problem

Answer 6

can someone help me with it or what

Answer 7

Thankfully, there is the quadratic formula... it's foolproof... you interested? :D

Answer 8

sure

Answer 9

Well, anytime you're ready, if you have a quadratic equation of the form
\[\Large \color{red}ax^2 + \color{blue}bx +\color{green}c = 0\]
Where, of course, a is not 0, then the solutions can be quickly obtained using this formula...
\[\LARGE x = \frac{-\color{blue}b \pm \sqrt{\color{blue}b^2 - 4\color{red}a\color{green}c}}{2\color{red}a}\]

follow this formula (carefully) and you can never go wrong with quadratic equations :D

Answer 10

Let's take the first one as an example... shall we? :)

Answer 11

okay

Answer 12

\[\Large \color{red}{16}x^2 -\color{blue}8x +\color{green}1 = 0 \]

In this case, what are your values for a,b, and c?

Answer 13

a=15 b=8 and c=1

Answer 14

Where did you get a = 15? lol
Also, note the minus-sign preceding the 8... better rethink your value for b....


With those said, what are the values for a,b, and c? :)

Answer 15

i meant 16 and -8 my fingers and laptop arennt behaving today as you can c

Answer 16

a=16 b=-8 c=1

Answer 17

LOL, it's fine :)
So
a = 16
b = -8
c = 1

Great :)
So, we plug them into the quadratic formula...
\[\LARGE x = \frac{-\color{blue}{(-8)}\pm \sqrt{\color{blue}{(-8)^2}- 4\color{red}{(16)}\color{green}{(1)}}}{2\color{red}{(16)}}\]

And just solve :)

Answer 18

8+-sqrt 64+64/32

Answer 19

@terenzreignz i dont know exactly how to do this from here

Answer 20

Okay, relax.. deep breaths :D

Answer 21

lol terenz. dont be so dramatic XD

Answer 22

\[\LARGE x = \frac{\color{blue}{(8)}\pm \sqrt{\color{blue}{64}- \color{red}{64}}}{\color{red}{32}}\]
Simplify. :)

Answer 23

8/32

Answer 24

simplify? :D

Answer 25

.25

Answer 26

so both answers are .25

Answer 27

Personally, I prefer 1/4, but whatever floats your boat :P

Answer 28

yay lol wanna keep helpin me i get the way you talk lol

Answer 29

I haven't said a word :D

Okay, do the second one, I'll watch for errors :)

Answer 30

liar! lol
2x^2-7x+3
a=2 b=-7 c=3
whats the quadratic formula?

Answer 31

\[\LARGE x = \frac{-\color{blue}b \pm \sqrt{\color{blue}b^2 - 4\color{red}a\color{green}c}}{2\color{red}a}\]

Answer 32

okay so -2+-sqrt2^2-4(-7)(3)/2(2)

Answer 33

then simplify to get -2=-sqrt88/4 now what? @terenzreignz

Answer 34

Why -2?
I thought b = -7 ?

Answer 35

shooot

Answer 36

okay hold on i got this

Answer 37

7+-sqrt25/4 thats right i know

Answer 38

Very good :)
Now simplify.

Answer 39

thats the problem do i actually square it and what do i do with the 7????

Answer 40

i end up with .5 and 3 when i simplify

Answer 41

YOu got
\[\Large \frac{7\pm \sqrt{25}}{4}\]

Answer 42

Which really means...
\[\Large \frac{7+\sqrt5}{4} \quad and \quad \frac{7-\sqrt5}{4}\]

Answer 43

why square root of 5

Answer 44

whoops... sorry replace that with square root of 25 :)

Answer 45

ok so seven plus 5 and seven -5 divide both by four

Answer 46

Yup :)
And those are your answers :D

Answer 47

3 and .5 i was right okay i need to do this one y^2-6y+2=0

Answer 48

so a= 1 b=-6 and c=2

Answer 49

Yes. Go ahead :D

Answer 50

6+5.2915/2=5.14575 6-5.2915/2=.35425

Answer 51

so 5.2 and.4

Answer 52

I wouldn't suggest approximating... leave it in radical form.

Answer 53

meaning

Answer 54

@terenzreignz

Answer 55

Meaning, leave it like this...
\[\Large \frac{6\pm \sqrt{36-8}}{2}=\frac{6\pm \sqrt{28}}{2}=\frac{6\pm 2\sqrt7}{2}=3\pm\sqrt7\]

Answer 56

oh ok

Answer 57

I'm sure you can do the others now :)

Answer 58

whered 3 come from

Answer 59

We divided by 2 (to get rid of that denominator)

Answer 60

oh