write an equation in slope-intercept form of the line that passes through the given points
(3, -2), (6,1)
@ajprincess Same way?
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OpenStudy (ajprincess):
have u found the slope using that formula?
OpenStudy (notamathgenius):
No c: i know nothing about slope intercept I dislike it a lot -_-
OpenStudy (ajprincess):
slope is found using the formula
\[slope~m=\frac{y_2-y_1}{x_2-x_1}\]
\[m=\frac{1-(-2)}{6-3}=?\]
OpenStudy (notamathgenius):
i got -1.666666667
OpenStudy (ajprincess):
nw can u find m?
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OpenStudy (ajprincess):
@notamathgenius
OpenStudy (notamathgenius):
hmmm
OpenStudy (ajprincess):
sure?
OpenStudy (notamathgenius):
Yea I am lost, i keep looking back at the question -_- grr i hate math
OpenStudy (ajprincess):
wht is 1-(-2)=?
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OpenStudy (notamathgenius):
3
OpenStudy (ajprincess):
good:)
nw what is 6-3=?
OpenStudy (notamathgenius):
3
OpenStudy (ajprincess):
good:)
3/3=?
OpenStudy (notamathgenius):
1
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OpenStudy (ajprincess):
good:) so what is m=?
OpenStudy (notamathgenius):
1 :D
OpenStudy (ajprincess):
yup. good:)
OpenStudy (notamathgenius):
Oh boy math is fun -_- not
OpenStudy (ajprincess):
nw
let us consider a point (x.y) on the same line. then
\[m=\frac{y-y_1}{x-x_1}\]
\[1=\frac{y-(-2)}{x-3}\]
\[1(x-3)=y+2\]
Slope-intercept equation is
\\[y=1(x-3)-2\]
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