Question

Help I have no idea how to do this! WIll become fan!

Answer 1

@JFraser help please?

Answer 2

the problem gives you Q, m, and Delta T, solve for C. This is also chemistry, not math

Answer 3

\[Q = m*C* \Delta T\]

Answer 4

Delta Q =M S delta T
S= Delta Q /M Delta T
put the values of
Delta Q , Delta T and Delta Q
and find the S

Answer 5

it's not asking for Delta S, it's asking a calorimetry question. not an entropy question

Answer 6

Could you set up the equation for me please? because Im not sure where each number goes? @JFraser

Answer 7

Okay, then you can continue to help. Don't mind me. Cx

Answer 8

@JFraser do you think you could set it up for me?

Answer 9

i just did.

read the question.

plug in the mass for m, the heat for Q, and the change in temp for DT

Answer 10

SO its A right? @JFraser

Answer 11

check the units of the heat you're given (KJ) and the units of heat the answers offer your (J). The answer is B

Answer 12

whenever you have to solev a problem in chemistry or physics, you never get just numbers. You always get units attached to every number. Look at the units, and that will tell you where each number goes.

Answer 13

I did, 0.52 = 17.0 x C x 3.6?

Answer 14

look at the units of heat. You're given KILOjoules

Answer 15

but the answer is in JOULES

Answer 16

so how did I change it?

Answer 17

0.520KJoules must be 520Joules\[0.520kiljoules * (\frac{1000 Joule}{1 kilojoule})\]

Answer 18

520?

Answer 19

the heat is 520 Joules, you have to keep all the units consistent

Answer 20

alright so this is false right
?

Answer 21

i don't really remember the difference between specific heat and specific heat capacity. one has units of J/C, one has units of J/(g*C). it might be false, i'm just not sure

Answer 22

alright thanks for your help. think you could help me with one more question? @JFraser

Answer 23

the copper is submerged in water because measuring the temp of the copper solid is difficult. The amount of energy the copper releases as it cools MUST be EQUAL TO the amount of energy the water absorbs. That's the whole reason why calorimetry works.

knowing the specific heat of copper isn't going to be much help, either

Answer 24

So its D ? @JFraser

Answer 25

it's not D

Answer 26

I ment C?

Answer 27

Wait no dont mind what I said. You said that spedific heat of copper will not help. so its either A or B?

Answer 28

yup, it's either A or B

Answer 29

is it A? im guessing.

Answer 30

because wouldnt it give off heat to the water, so by knowing the temp changes in the water we would know more about the thermal energy of the copper?

Answer 31

so it is A right, @JFraser

Answer 32

what do all the pieces of data in A all have in common? they're all referring to the same thing: the water.


the water does the absorbing of the energy that the copper releases.

the answer is A

Answer 33

Thanks so much for your help..!(: