Question

i need help

Answer 1

\[\sqrt{8x+1}=5\]
\[\sqrt{x-7}+5=11\]
\[-4\sqrt{x+9}=20\]
\[\sqrt{6x+5}=\sqrt{53}\]
\[\sqrt{x+2}+4=x\]

Answer 2

\(\sqrt{8x+1}=5\)
square both sides and u will get
\((\sqrt{8x+1})^2=5^2\)
\(8x+1=25\)
solve for x. Does that help? @ladiesman217

Answer 3

um ya

Answer 4

so vat is x?

Answer 5

3

Answer 6

yup good:)

Answer 7

so the second one is\[(\sqrt{x-7}+5)^{2}=11^2\]

Answer 8

moving on to the next question
\[\sqrt{x-7}+5=11\]
Subtract 5 both sides. then u will get
\[\sqrt{x-7}+5-5=11-5\]
\[\sqrt{x-7}=6\]
Square both sides
\[(\sqrt{x-7})^2=6^2\]

Answer 9

when solving problems like this it is always advisable to isolate the expressions with square root signs

Answer 10

Does that help?