Question

Sara selects two cards at random from a standard deck of cards. Which of the following could be used to calculate the probability that she will select two numbered cards if she does not replace the first card before selecting the second? Note: For this problem, face cards and aces are not numbered cards.
A-36/52 35/51
B-36/52 35/52
C-36/52 36/52
D-36/52 36/51

Answer 1

1. None of these works for the problem as you have described it. If you had said "odd" instread
of "even", then B would be your answer. For picking odd numbers, you'd have the
3, 5, 7, and 9 each of which occurs 4 times for a total of 16 good picks out of 52 cards.
This gets you 16/52 for the first fraction. After picking 1 odd card without replacement you would
then have 15 odd cards left in a deck of 51 cards, which gets you the 15/51 for the 2nd fraction.

The reason that this doesn't work for "even" is that you have 2, 4, 6, 8, 10. So the numbers
on the top of the fractions would have to be 20 and 19.

Answer 2

ok thanks :)

Answer 3

Medal?

Answer 4

yea @SamuelAlden917

Answer 5

lol