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Mathematics 10 Online
OpenStudy (anonymous):

Express In Simplest Form vvvv

OpenStudy (anonymous):

\[45a ^{4}b ^{3} - 90a ^{3}b \div 15a ^{2}b\]

OpenStudy (anonymous):

^ Express in Simplest Form

jimthompson5910 (jim_thompson5910):

hint: factor out 15a^2b from the numerator

OpenStudy (anonymous):

you mean denominator?

jimthompson5910 (jim_thompson5910):

no the numerator

jimthompson5910 (jim_thompson5910):

factor out 15a^2b from 45a^4b^3 - 90a^3b

OpenStudy (anonymous):

but the 15a^2b^3 is in the denominator

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

sorry im really confused

jimthompson5910 (jim_thompson5910):

how so

OpenStudy (anonymous):

would it be 15a^3b (45a^4b^3 - 90a^3b)

OpenStudy (anonymous):

and then factor that?

jimthompson5910 (jim_thompson5910):

yes but if you distribute 15a^3b (45a^4b^3 - 90a^3b), you won't get 45a^4b^3 - 90a^3b

OpenStudy (anonymous):

you get 3ab^2-6

OpenStudy (anonymous):

but im confused about what to do next

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

well once you factor out 15a^3b, you get 15a^3b(3ab^2-6) in the numerator

jimthompson5910 (jim_thompson5910):

the 15a^3b terms will then cancel (numerator and denominator pairing)

OpenStudy (anonymous):

whats the denominator?

jimthompson5910 (jim_thompson5910):

when you cancel out the 15a^3b term in the denominator, you'll be left with a 1 in the denominator

jimthompson5910 (jim_thompson5910):

but anything over 1 is itself ex: 10/1 = 10 or 22/1 = 22

jimthompson5910 (jim_thompson5910):

so the final answer is just 3ab^2-6

OpenStudy (anonymous):

no before you cancel out what is the equation thats what im confused about

jimthompson5910 (jim_thompson5910):

oh wait...idk why i didn't catch this before, it's 15a^2b not 15a^3b let me redo the whole thing, one sec

jimthompson5910 (jim_thompson5910):

\[\large \frac{45a ^{4}b ^{3} - 90a ^{3}b}{15a ^{2}b}\] \[\large \frac{15a^2b(3a^2b^{2} - 6a)}{15a ^{2}b}\] \[\large \frac{\cancel{15a^2b}(3a^2b^{2} - 6a)}{\cancel{15a^2b}}\] \[\large \frac{3a^2b^{2} - 6a}{1}\] \[\large 3a^2b^{2} - 6a\]

OpenStudy (anonymous):

ohh that makes sense!! THANK YOU SO MUCH FOR THE HELP!

jimthompson5910 (jim_thompson5910):

you're welcome

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