Mathematics
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OpenStudy (anonymous):
Express In Simplest Form
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OpenStudy (anonymous):
\[45a ^{4}b ^{3} - 90a ^{3}b \div 15a ^{2}b\]
OpenStudy (anonymous):
^ Express in Simplest Form
jimthompson5910 (jim_thompson5910):
hint: factor out 15a^2b from the numerator
OpenStudy (anonymous):
you mean denominator?
jimthompson5910 (jim_thompson5910):
no the numerator
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jimthompson5910 (jim_thompson5910):
factor out 15a^2b from 45a^4b^3 - 90a^3b
OpenStudy (anonymous):
but the 15a^2b^3 is in the denominator
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
sorry im really confused
jimthompson5910 (jim_thompson5910):
how so
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OpenStudy (anonymous):
would it be 15a^3b (45a^4b^3 - 90a^3b)
OpenStudy (anonymous):
and then factor that?
jimthompson5910 (jim_thompson5910):
yes but if you distribute 15a^3b (45a^4b^3 - 90a^3b), you won't get 45a^4b^3 - 90a^3b
OpenStudy (anonymous):
you get 3ab^2-6
OpenStudy (anonymous):
but im confused about what to do next
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
well once you factor out 15a^3b, you get
15a^3b(3ab^2-6)
in the numerator
jimthompson5910 (jim_thompson5910):
the 15a^3b terms will then cancel (numerator and denominator pairing)
OpenStudy (anonymous):
whats the denominator?
jimthompson5910 (jim_thompson5910):
when you cancel out the 15a^3b term in the denominator, you'll be left with a 1 in the denominator
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jimthompson5910 (jim_thompson5910):
but anything over 1 is itself
ex: 10/1 = 10 or 22/1 = 22
jimthompson5910 (jim_thompson5910):
so the final answer is just 3ab^2-6
OpenStudy (anonymous):
no before you cancel out what is the equation thats what im confused about
jimthompson5910 (jim_thompson5910):
oh wait...idk why i didn't catch this before, it's 15a^2b not 15a^3b
let me redo the whole thing, one sec
jimthompson5910 (jim_thompson5910):
\[\large \frac{45a ^{4}b ^{3} - 90a ^{3}b}{15a ^{2}b}\]
\[\large \frac{15a^2b(3a^2b^{2} - 6a)}{15a ^{2}b}\]
\[\large \frac{\cancel{15a^2b}(3a^2b^{2} - 6a)}{\cancel{15a^2b}}\]
\[\large \frac{3a^2b^{2} - 6a}{1}\]
\[\large 3a^2b^{2} - 6a\]
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OpenStudy (anonymous):
ohh that makes sense!! THANK YOU SO MUCH FOR THE HELP!
jimthompson5910 (jim_thompson5910):
you're welcome