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How would I simplify this rational expression?
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\[\frac{2a^2 - 4a + 2 }{3a^2-3 }\]
First, factor the numerator and denominator.
Add like terms
\[2a^{2}-4a+2=2(a^{2}-2a+1)=2(a-1)^{2}\]\[3a^{2}-3=3(a+1)(a-1)\]Factor out what you can.
There are no like terms to be added.
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Then do I cancel out the like expressions? {(a-1)}?
2/3?
\[\frac{2(a-1)(a-1) }{3(a-1)(a+1) }=\frac{ 2(a-1) }{ 3(a+1) }\]
Ohhh. Thank you. So, what would the excluded value be for this expression?
I can't think of any value that would make the expression undefined.
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Nevermind, \[a \neq1, a \neq-1\]
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