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Mathematics 8 Online
OpenStudy (anonymous):

three cards are drawn from a standard deck of 52 cards without replacement. what is the probability that all three cards are kings?

OpenStudy (anonymous):

2/11050

OpenStudy (anonymous):

4*3*2/52*51*50 which equals 24/132600 then simplify

OpenStudy (anonymous):

Well there are 4 kings, which means you have a 7.7% chance of drawing any of them on the first try. After that, you will have 3 left and 51 cards, which is a 5.9% chance. The 3rd time, 2 kings and 50 cards, so 4% chance. All you have to do to find the chance to do all of these simultaneously is multiply the percentages. .077*.059*.04=.0001, which is .01% chance.

OpenStudy (anonymous):

thank you :)

OpenStudy (anonymous):

I'm supposed to get the answer of 1/5,525

OpenStudy (anonymous):

oh sorry 2/11050 simplifies to 1/5525

OpenStudy (anonymous):

my bad

OpenStudy (anonymous):

Oh actually the decimal rounds up to .02%, which is very close to your fraction.

OpenStudy (anonymous):

thank you beautiful :)

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