A limb with mass 14 kg falls out of a tree from a height of 3.5 m. How much mechanical energy does the limb have just before it hits the ground? (Assume there is no air resistance.) A. 480.2 J B. 355.3 J C. 0 J D. 49 J
There are two ways you could go about this: Calculating the kinetic energy as a function of the limb's end-velocity, or calculating the limb's potential energy from its point of origin somewhere above the ground. The latter is the easiest. \[U=F*d\] U is the potential energy of an object with force F at a distance d above the ground. When the limb falls toward the ground, the potential energy is very rapidly converted to mechanical energy - they are two sides of the same coin, which is why we can find the size of one by calculating the other.
\[U=K\] when the limb is infinitesimally close to the ground.
I don't understand anything you said. I'm sorry, I really just can't understand physics I guess.
limb possess potential energy, P.E.=mgh \[=14\times9.8\times3.5\] =480.2 J Hence the answer is A I guess so, but please confirm.
That's exactly it!
Join our real-time social learning platform and learn together with your friends!