can 4x^2-3y^2 factorize? pls help im stuck
It can, but you have root 3 y in there.
? sorry I don't understand what do you mena by root 3y
\[a^2-b^2=(a+b)(a-b)\] \[4x^2-3y^2=(2x)^2-(\sqrt3 y)^2\]
:( i'm not getting it, sigh so frustrating.
It is basically a simple "identity" generally the rule you are using here to find this is a^2 - b^2 = (a - b) (b - a) Do you get this so far?
@Christos yeah i learned that bit so far but I cannot find the right combination. we were taught that to factorize something it looks like (a+b)(a-b) but i don't get how it becomes (2x)^2 - (sqroot of 3y)^2 ?
nvm i get how it becomes that... but, that form wasn't taught to us. we were always taught the (a+b)(a-b) form which we then use to divide...... does (2x)^2 - (sqroot3)^2 change into a (a+b)(a-b) form?
You've formatted it as a^2-b^2, so yes.
ok so basically it's just the sq root of first term - sq root of seond term x sq root of first term + sq root of second term?
yeah
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