Question

Please HELP me ): , i am stuck ..
Suppose that y varies inversely with x, and y = 2 when x = 6. What is an equation for the inverse variation?

Answer 1

\[ y = \frac{k}{x}\]
solve for k using given info
\[2 = \frac{k}{6}\]

Answer 2

/: im confused :(

Answer 3

the equation for inverse variation is:
\[y = \frac{k}{x}\]
where "k" is some constant
so solve for k and you are done

Answer 4

how do i solve for k ?

Answer 5

plug in x=6 and y=2

Answer 6

@Luis_Rivera , help me .

Answer 7

am i and @Callisto not helping you ?

Answer 8

your confusing me. im trying to plug it in, but then idk how to solve it. ): im just now learning how to do these problems.

Answer 9

@adl_thoo , Show an attempt first

Answer 10

I have :( im just learning how to do these. ive plugged it in, now how do i solve . thts where im stuck at.

Answer 11

what did u "plug in " ?

Answer 12

okay, i plugged in what they said & i got : 2=6/x

Answer 13

look

Answer 14

oka

Answer 15

k

Answer 16

o.O huh

Answer 17

lol, that ,means ok

Answer 18

lmao, i know it.

Answer 19

@eSpeX , help me here ?

Answer 20

What is it that you're not getting?

Answer 21

how to solve the equation . im very confused .

Answer 22

x=y/4
y=12/x
y=4x
y=x/12

Answer 23

those are my answers, i cant seem to get any of them

Answer 24

Okay, the problem tells you that the relation between x and y is an inverse relationship. This means that as y increases, x decreases.

Answer 25

Right . soo ?

Answer 26

As @dumbcow pointed out, your relationship is written as \[y=\frac{k}{x}\] and they give you the values of x and y.

Answer 27

which means : 2=6/x

Answer 28

So looking at your values and the potential answers, what (k) can you divide by x (6) that will give you y (2)?

Answer 29

12 ?

Answer 30

\[\boxed{\color{#E32}{\text{great job!}}}\]

Answer 31

so my answers is B ?

Answer 32

So looking at your answers, do you have something that looks like \[y=\frac{12}{x}\] ?

Answer 33

Yes, nice work.

Answer 34

yes, B :D

Answer 35

thank you so much !

Answer 36

You're welcome.