If sin y = a/6 and tan y = a/b what is the value of cos y?
answer choices: cos y = 6/b cos y = 6a cos y = 6b cos y = b/6
Use tanx = sinx/cosx
can you rearrange Christos's forumla for cosx @kaylakitty?
I'm still confused, I know that cos = adjacent/hypotenuse, and I know how to find cos but I don't get this question
Well first of all on this question you are not gonna use cos = adjacent/hypotenuse STEP 1: tan y = sin y/cos y STEP 2: tan y/sin y = 1/cos y STEP 3: replace tan, sin, and cos with the values you already got Can you do this for starters?
Correction STEP 3: Just replace tan and sin
I'm still confused :/
About what exactly?
I know how to solve for tan, sin, and cos when it's on a triangle with the degrees, like this question just confuses me, idk
Do you know how to solve this x*6 -3 = 3 ? What's the value of x?
yes, it's 1
x=1*
\[\boxed{\sin\theta=\tfrac{\text{opposite side}}{\text{hypotenuse}}},\qquad\boxed{\cos\theta=\tfrac{\text{adjacent side}}{\text{hypotenuse}}},\qquad\boxed{\tan\theta=\tfrac{\text{opposite side}}{\text{adjacent side}}}\] \[\frac{\sin\theta}{\cos\theta}=\frac{\tfrac{\text{opposite side}}{\text{hypotenuse}}}{\tfrac{\text{adjacent side}}{\text{hypotenuse}}}=\frac{\tfrac{\text{opposite side}}{\color{red}{\cancel{\color{black}{\text{hypotenuse}}}}}}{\tfrac{\text{adjacent side}}{\color{red}{\cancel{\color{black}{\text{hypotenuse}}}}}}=\frac{\text{opposite side}}{\text{adjacent side}}=\tan\theta\]
Correct. Back to my STEP 3. tan y/sin y = 1/cos y -----> (a/b)/(a/6)= 1/cosy What's the value of cosy?
b=6cos(y) so cos y = 6b?
No but, pretty close.
its cos(y) = b/6 (4th choice) when you change sides of the coefficient (6) , the coefficient, becomes goes in the place of the denominator it is no longer a multiplication.
goes in the place*
Oh, okay I get it, thank you (:
Np
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