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Sketching complexes
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Question 3(ii)
From i) I've got w=2+i \[w^2=(2+i)^2 \\ \\ w^2=4+4i+4i^2 \\ \\ w^2=3+4i\]
Modulus of \(w^2\) is \(|w^2|=\sqrt{9+16}=5\)
How do I sketch \[|z-w^2| \leq |w^2|\]
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\[w^2=(2+i)^2=4+4i+i^2=4+4i-1=3+4i\]
|dw:1368600327852:dw|
|dw:1368600390162:dw|
|dw:1368600627818:dw|
Is it correct?
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i think so, but im not sure about where to shade
hmm, the marking scheme is here, maybe it'll help http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w10_ms_33.pdf
oh its a circle
we can see from \(|z-w^2|\leq|w^2|\), that if \(z\) is in the same direction as \(w\) ; \(z\) must be \(0\leq z\leq2w^2\)
|dw:1368601622693:dw|
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