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Mathematics 8 Online
OpenStudy (calculator):

Sketching complexes

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Question 3(ii)

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From i) I've got w=2+i \[w^2=(2+i)^2 \\ \\ w^2=4+4i+4i^2 \\ \\ w^2=3+4i\]

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Modulus of \(w^2\) is \(|w^2|=\sqrt{9+16}=5\)

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How do I sketch \[|z-w^2| \leq |w^2|\]

OpenStudy (unklerhaukus):

\[w^2=(2+i)^2=4+4i+i^2=4+4i-1=3+4i\]

OpenStudy (unklerhaukus):

|dw:1368600327852:dw|

OpenStudy (calculator):

|dw:1368600390162:dw|

OpenStudy (unklerhaukus):

|dw:1368600627818:dw|

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Is it correct?

OpenStudy (unklerhaukus):

i think so, but im not sure about where to shade

OpenStudy (calculator):

hmm, the marking scheme is here, maybe it'll help http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w10_ms_33.pdf

OpenStudy (unklerhaukus):

oh its a circle

OpenStudy (unklerhaukus):

we can see from \(|z-w^2|\leq|w^2|\), that if \(z\) is in the same direction as \(w\) ; \(z\) must be \(0\leq z\leq2w^2\)

OpenStudy (unklerhaukus):

|dw:1368601622693:dw|

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